Quadratic Formula Calculator
Advanced Tool for Solving Quadratic Equations and Analyzing Parabolas
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Solve Quadratic Equation
Solve ax² + bx + c = 0
Analyze Quadratic Properties
Get complete analysis of the parabola
What is the Quadratic Formula?
The quadratic formula is a method for solving any quadratic equation of the form ax² + bx + c = 0. It provides the roots (solutions) regardless of whether they are real or complex. The formula is one of the most fundamental tools in algebra and appears throughout mathematics, physics, engineering, and many other fields.
The formula is: x = [-b ± √(b² - 4ac)] / 2a. It uses the coefficients of the equation to calculate exact solutions. The ± symbol indicates there are typically two solutions, one using addition and one using subtraction.
The discriminant (b² - 4ac) is the critical component that determines the nature of the solutions. If it's positive, you get two distinct real roots. If it's zero, you get one repeated real root. If it's negative, you get two complex conjugate roots.
Key Features & Capabilities
This comprehensive quadratic calculator provides multiple analysis modes and detailed solutions:
How to Use This Calculator
Step-by-Step Guide
- Identify the Mode: Choose "Solve" to find roots or "Analyze" for comprehensive parabola analysis including vertex, symmetry, and discriminant.
- Get Your Equation in Standard Form: Write your quadratic as ax² + bx + c = 0. If it's not in standard form, rearrange it first.
- Identify Coefficients: Extract the values: a (coefficient of x²), b (coefficient of x), and c (constant term). Include signs (negative or positive).
- Enter Values: Input a, b, and c into the calculator. Note that a must be non-zero for a true quadratic equation.
- Click Solve or Analyze: Press the button to calculate. For "Solve," you get the roots. For "Analyze," you get complete properties.
- Review Results: The main result displays the solutions. For "Solve," you see the roots in simplified form.
- Study the Breakdown: See detailed steps showing the discriminant calculation, quadratic formula application, and simplification.
- Understand Additional Information: The statistics box shows vertex, axis of symmetry, discriminant interpretation, and parabola direction.
Tips for Accurate Use
- Sign Convention: Include the sign with each coefficient. For x² - 5x + 6 = 0, enter a=1, b=-5, c=6.
- Standard Form Required: Ensure equation is in ax² + bx + c = 0 form before entering coefficients.
- Non-Zero a: Verify a ≠ 0. If a = 0, it's not quadratic and the formula doesn't apply.
- Complex Roots: When discriminant is negative, roots are complex conjugates (involves i = √-1).
- Verification: Always verify by substituting roots back into the original equation.
Complete Formulas Guide
The Quadratic Formula
ax² + bx + c = 0x = [-b ± √(b² - 4ac)] / 2aWhere:
a = coefficient of x² (a ≠ 0)
b = coefficient of x
c = constant term
Example: For x² - 5x + 6 = 0
x = [5 ± √(25 - 24)] / 2 = [5 ± 1] / 2
x = 3 or x = 2
Discriminant
Δ = b² - 4ac (discriminant)If Δ > 0: Two distinct real roots
If Δ = 0: One repeated real root
If Δ < 0: Two complex conjugate roots
Example: For x² - 5x + 6 = 0
Δ = (-5)² - 4(1)(6) = 25 - 24 = 1 > 0
Therefore: Two distinct real roots
Vertex Coordinates
x-coordinate (axis of symmetry): x = -b / 2ay-coordinate: y = c - b² / 4aOr substitute x-coordinate into original equation
Example: For x² - 5x + 6 = 0
x = 5 / 2 = 2.5
y = 6 - 25/4 = 24/4 - 25/4 = -1/4 = -0.25
Vertex: (2.5, -0.25)
Vertex Form
y = a(x - h)² + kWhere (h, k) is the vertex
Example: x² - 5x + 6 = 0 becomes
y = 1(x - 2.5)² - 0.25
or: y = (x - 2.5)² - 1/4
Relationship Between Roots and Coefficients
Sum of roots: r + s = -b/aProduct of roots: r × s = c/aExample: For x² - 5x + 6 = 0
Roots: 2 and 3
Sum: 2 + 3 = 5 = -(-5)/1 ✓
Product: 2 × 3 = 6 = 6/1 ✓
Real-World Applications
Physics - Projectile Motion
The height of a projectile follows a quadratic equation: h(t) = -16t² + v₀t + h₀. Solving using the quadratic formula gives times when the projectile is at ground level or at a specific height.
Business - Break-Even Analysis
Profit functions often form quadratics: P(x) = -x² + 100x - 1000. Finding roots determines break-even points where profit equals zero.
Engineering - Structural Design
Load calculations and stress distributions often involve quadratic relationships. The quadratic formula helps find critical dimensions and maximum loads.
Finance - Investment Returns
Compound interest and growth models sometimes simplify to quadratic equations for optimization and break-even analyses.
Chemistry - Equilibrium Calculations
Chemical equilibrium problems often produce quadratic equations for concentration calculations in certain reaction types.
Statistics - Normal Distribution
Quadratic equations appear in statistical analysis, particularly in variance calculations and distribution analysis.
Worked Examples
Example 1: Simple Quadratic with Two Real Roots
Problem: Solve x² - 5x + 6 = 0
Coefficients: a = 1, b = -5, c = 6
Discriminant: Δ = (-5)² - 4(1)(6) = 25 - 24 = 1
x = [5 ± √1] / 2
x = [5 ± 1] / 2
x₁ = (5 + 1) / 2 = 6 / 2 = 3
x₂ = (5 - 1) / 2 = 4 / 2 = 2
Verification:
x = 3: 3² - 5(3) + 6 = 9 - 15 + 6 = 0 ✓
x = 2: 2² - 5(2) + 6 = 4 - 10 + 6 = 0 ✓
Example 2: Quadratic with One Repeated Root
Problem: Solve x² - 4x + 4 = 0
Coefficients: a = 1, b = -4, c = 4
Discriminant: Δ = (-4)² - 4(1)(4) = 16 - 16 = 0
x = [4 ± √0] / 2 = 4 / 2 = 2 (repeated root)
This means: (x - 2)² = 0, or x = 2 with multiplicity 2
The parabola touches the x-axis at exactly one point
Example 3: Quadratic with Complex Roots
Problem: Solve x² - 2x + 5 = 0
Coefficients: a = 1, b = -2, c = 5
Discriminant: Δ = (-2)² - 4(1)(5) = 4 - 20 = -16
x = [2 ± √(-16)] / 2
x = [2 ± 4i] / 2
x = 1 ± 2i
Two complex conjugate roots: x₁ = 1 + 2i, x₂ = 1 - 2i
The parabola never crosses the x-axis (no real roots)
Example 4: Projectile Motion
Problem: A ball is thrown upward at 48 ft/s from a 64 ft cliff. When does it hit the ground? (h = -16t² + 48t + 64)
Set h = 0: -16t² + 48t + 64 = 0
Divide by -16: t² - 3t - 4 = 0
Coefficients: a = 1, b = -3, c = -4
Discriminant: Δ = 9 - 4(1)(-4) = 9 + 16 = 25
t = [3 ± 5] / 2
t = 4 or t = -1
Since time must be positive: t = 4 seconds
The ball hits the ground after 4 seconds
Example 5: Finding Vertex and Axis of Symmetry
Problem: For y = 2x² - 8x + 5, find vertex and axis of symmetry
Coefficients: a = 2, b = -8, c = 5
Axis of symmetry: x = -b / 2a = 8 / 4 = x = 2
Vertex y-coordinate: y = 2(2)² - 8(2) + 5
y = 8 - 16 + 5 = -3
Vertex: (2, -3)
Parabola opens upward (a > 0), so vertex is the minimum
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